
比赛以AK收尾,但是其中1道题非常规做出,一道题AI做的,后续非常规的题仍未解出,待WP发布后更新
1.CHECK IN
题干:可以分析得到是一道简单的近似忽略
from sage.all import *
from Crypto.Util.number import getStrongPrime, inverse
from hashlib import *
while True:
p = getStrongPrime(512)
q = getStrongPrime(512)
if p%4==3 and q%4==3:
print(p,q)
break
N = p * q
phi_N = (p**2 + p + 1) * (q**2 + q + 1)
d = Integer(N)**RR(0.47)
e = inverse(Integer(d), phi_N)
flag='flag{'+md5(str(p+q).encode()).hexdigest()+'}'
print(f"e = {e}")
print(f"N = {N}")
print(flag)
"""
e = 20285928988408708385825788658664300305494782819689883492429762785687493161646901961627732482030570554944571523044008931416609595056746847083499405860944240804200816473153171825246196297214879750749954991916614158499347588230595409852985660426387332691700171974951765953937059128044510635005259571262430221092123685629379451869171518153057333553882827808279895371867053070597655168641441209936240962391624079704514097507822408340977683148014817264999772615710237278286803551400605422497036878844692741788304043681532328471441465596285604159664321904195632202009921776619257725630740166796422445907541165144233376010917
N = 162318864198120848289602513685294100213662002310524040016141267082602211702801751627271587107738223466644399363879018058536864307889254050305605097781721847474240769410050480646447538698253600786017599233831714710010395996308361674973789283465587010960323042209564459904257042660293061844258544118566558516881
"""
WP:属于常见题型,不展开分析
#签到题,正常的近似忽略处理,左右爆破
#核心漏洞出现在phi的量级处理上,泄露了n量级接近
#还直接给出了d
#主要的讲解在于offset的区域讨论,量级估计
from hashlib import md5
e = 20285928988408708385825788658664300305494782819689883492429762785687493161646901961627732482030570554944571523044008931416609595056746847083499405860944240804200816473153171825246196297214879750749954991916614158499347588230595409852985660426387332691700171974951765953937059128044510635005259571262430221092123685629379451869171518153057333553882827808279895371867053070597655168641441209936240962391624079704514097507822408340977683148014817264999772615710237278286803551400605422497036878844692741788304043681532328471441465596285604159664321904195632202009921776619257725630740166796422445907541165144233376010917
N = 162318864198120848289602513685294100213662002310524040016141267082602211702801751627271587107738223466644399363879018058536864307889254050305605097781721847474240769410050480646447538698253600786017599233831714710010395996308361674973789283465587010960323042209564459904257042660293061844258544118566558516881
d = Integer(Integer(N)**RR(0.47))
K = e * d - 1
#这里的K是t*phi,可以易得phi得量级接近N**2,仔细计算下来是N**2*(1+2**(-513))
#可以近似处理,直接K//N**2来估算t,根据上面可以得到t在1附近,左右offset10差不多了
k_est = K // (N**2)
k = None
for offset in range(-10, 11):
if K % (k_est + offset) == 0:
k = k_est + offset
break
phi_N = K // k
#接下来是一个S^2 + (N+1)S + (N^2 - N + 1 - phi_N) = 0 得方程,一元二次公式解决
A = 1
B = N + 1
C = N**2 - N + 1 - phi_N
Discriminant = B**2 - 4*A*C
if Discriminant.is_square():
S = (-B + Discriminant.sqrt()) // (2*A)
flag_str = 'flag{' + md5(str(S).encode()).hexdigest() + '}'
print(f"[+] {flag_str}")
else:
print("[-] 求解失败:判别式不是完全平方数。")
典型的近似忽略
2.签到
题干:
天命战队通过专业技术发现线索:2月28日凌晨,伊朗革命卫队某电报群紧急发送一条消息后立即撤回。有群成员截图了撤回通知,但只看到“这条消息已被撤回”。实际上,撤回的消息仍会短暂留在本地缓存中。
天命战队专家提取到了撤回消息的文本并翻译:“坐标25.1°N, 51.3°E,目标确认,行动代号:0100---ZRPEA===ZWHCQ===Y2K7A===ZJNCA===”
WP:
这道题没有用解码,而是用了osint的思路
结合题目上背景,得到伊朗,2.28,经纬度3个关键词
先从经纬度入手,得到美军乌代德空军基地这个地址,再发散结合日期,伊朗搜索信息
看到以下报告:https://www.backchina.com/news/2026/03/06/1017907.html
搜索伊朗相关报告,得到名称
真实承诺4(Operation True Promise 4)
4与0100相符,大概就是
flag{真实承诺4}
base32?
3.尽人事,听天命
题目上有很多的干扰信息,实则看到623.75时识别出题型MT19937,发现刚好就给了连续的623.75组数据,爆破一组,逆向temper预测
题干:
import random
from secret import seed,yin,yang
signs = ['大吉', '中吉', '小吉', '吉', '末吉', '凶', '大凶']
colors = ['赤', '橙', '黄', '青', '蓝', '紫', '黑', '白']
pool = []
count = 2495
bits = 32
kbits = 6
def next_omen():
global pool
if not pool:
x = random.getrandbits(32)
pool = [x & 0xff, (x >> 8) & 0xff, (x >> 16) & 0xff, (x >> 24) & 0xff]
return pool.pop(0)
def make_book(name):
t = next_omen()
a = t % 101
b = (t * 3 + 7) % 101
c = (t * 5 + 11) % 101
d = (t * 7 + 13) % 101
color = colors[t & 7]
sign = signs[(t >> 1) % len(signs)]
return '\n'.join([
'【天命阁命书】',
f'有缘人:{name}',
f'命途:{a}',
f'福缘:{b}',
f'财势:{c}',
f'劫数:{d}',
f'吉色:{color}',
f'签文:{sign}',
f'天命:{t}'
])
def pull(k):
x = 0
off = 0
while off < k:
x |= random.getrandbits(32) << off
off += 32
return x & ((1 << k) - 1)
def main():
random.seed(seed)
names = [f'有缘人{i:04d}' for i in range(count)]
with open('命书.txt', 'w', encoding='utf-8') as f:
f.write('天命阁旧录\n')
f.write('知天命,可窥未来。\n')
f.write('见未来,方知真形。\n\n')
for name in names:
f.write(make_book(name))
f.write('\n\n')
bound = yin * yang
trace = yin ^ (yang >> kbits)
seal_a = bound ^ pull(bits * 2)
seal_b = trace ^ pull(bits)
f.write('【未来残页】\n')
f.write(f'阴阳交积封印:{seal_a}\n')
f.write(f'阴阳离合封印:{seal_b}\n')
f.write('\n')
f.write('flag = DesCTF{md5(str(min(yin,yang)) + "|" + str(max(yin,yang)))}\n')
if __name__ == '__main__':
main()
#具体的数据命书就不展开了
WP:
#先回顾一下MT19937的基础知识,再展开这道题的设计
#&的运算,本质是模2乘,对于b'1'流,可以复制b'1'约束下的位数
#|的运算,本质是有1则1,^本质是模2加,这些运算优先级都低于<<
#pop{0}为输出列表中的第一个,后者进位,以便输出所有
#这道题目给了2495组输出,本质是623.75组,需要爆破0.25达到可破解MT19937,之后
#预测seal的输出,得到方程求解
#我先放脚本,再解释
import random
import re
from hashlib import md5
def untemper(y):
y ^= (y >> 18)
y ^= (y << 15) & 0xefc60000
temp = y
for _ in range(7):
y = temp ^ ((y << 7) & 0x9d2c5680)
temp = y
y = temp ^ (y >> 11)
y = temp ^ (y >> 11)
return y & 0xffffffff
#我先完整的讲一遍MT19937运算,以便理解为什么只用逆向temper
#seed(32)-初始化至624*32(state)-twist得到state[i]-temper-输出
#所以只用逆向temper,恢复到state[i]内部状态,接下来程序继续进行ex(实则是624用完进入twist),达到预测
#进入下一组也只用上一组的数据,不需要种子(详见twist)
#接下来是为什么可以这么恢复,根本原因是线性
#^可逆向,具有可逆性(再算一遍就可以了),>>实际展开来看,高位没有污染,低位的污染来源
#于高位的xor,可以恢复,视觉上最后就是反一下号就可以了
#然后对于<<,移除了的空了0位出来,反而可以直接得到,展开发现是000000123456和123456
#789,逐步恢复(这一步推荐上纸笔),循环//+1次
#^使得mask为1的才异或,0的变0.完全可逆
def get_factors(n):
factors = set()
for i in range(1, int(n**0.5) + 1):
if n % i == 0:
factors.add(i)
factors.add(n // i)
return factors
#这一步是找因子
def solve():
with open('命书.txt', 'r', encoding='utf-8') as f:
content = f.read()
seal_a = int(re.findall(r'阴阳交积封印:(\d+)', content)[0])#正则匹配
#具体语法:匹配\d表示数字,+表示至少一个,()表示提取类容
#findall表示返回列表,[0]第一个
seal_b = int(re.findall(r'阴阳离合封印:(\d+)', content)[0])
omens = [int(x) for x in re.findall(r'天命:(\d+)', content)]
outputs = []
for i in range(0, 2492, 4):
val = omens[i] | (omens[i+1] << 8) | (omens[i+2] << 16) | (omens[i+3] << 24)
outputs.append(val)
#这一步是提取数据,把随机数整合起来,切割成32的块
for last_byte in range(256):
val_624 = part_624 | (last_byte << 24)
current_outputs = outputs + [val_624]
state = [untemper(x) for x in current_outputs]#逆向temper
random.setstate((3, tuple(state + [624]), None))
#这里是状态设定,MT19937类型固定3,位置,缓存
r_low = random.getrandbits(32)
r_high = random.getrandbits(32)
r64 = r_low | (r_high << 32)
#一下是因子寻找解方程
for yin in get_factors(bound):
yang = bound // yin
if yin ^ (yang >> 6) == trace:
print(f"\n[+] 匹配成功!")
print(f" yin: {yin}, yang: {yang}")
res = sorted([yin, yang])
flag_str = f"{res[0]}|{res[1]}"
print(f" Flag: DesCTF{{{md5(flag_str.encode()).hexdigest()}}}")
return
if __name__ == "__main__":
solve()
MT19937预测破解
4.low bit high risk
一看就知的HNP问题板子
题干:
from sage.all import *
from hashlib import md5
q = 0x100000000000000000001f4c8f927aed3ca752257
pubx = 0x8e0a0071e8cf437efec4233ff8444a4ff8adba2f
puby = 0xa869fce702b70799c443b450a4d41cc4f65b3eee
leak = 3
B = 2^leak
data = [
(0x525931a9ff8ef95025939a57275ecedc2730421f,0x5288ed7146c188ebda9b6c8909726c3d6f957891,0x334c301c2d861fa8cceecabc542a5cb7dd7df7d9,0x6),
(0x4b21047e1112dbfee487b4f23471f2fb438e268,0x82878368ef18996109bf10adae81e1acaeb9fa25,0xd4d9ec1faa9534a3fa4ff0fe78488ebf175cdfec,0x4),
(0xdd2e98102508e178fdf1e289ac8342250da6408f,0x38069b3213a57a077a38938d082a7590d0a21b95,0xcff1f76af8f15422bb288c8af372332cc6ace970,0x1),
(0xecb8547ea2a68788665e01a7025093c47f2b45de,0x6f7155ce9da5434227e48554a0bef7d7492cadb,0x53f6e1a52554436620b392dea75738b5f670d2b2,0x2),
(0xefb887600edf8d279f3cca868ef641e9284ae769,0x9caea57dd4681d1ab53029cf631a47277386bc72,0xce7743df557c732daff4595d8430ea8485ab3aca,0x3),
(0x957ec8b7a53dea95d53a5c94d595b834c2be61ca,0x1b24031194de7dac370a2f7c9be316dc14cbe3f2,0xc40b5c4c674d1f4cb99891bf342f8acebca9258b,0x5),
(0x8ba1946c16b7c8d98c6e01836ae0d791ecae07d9,0x6daec7923c03c56a18d764d9497c39871912fb1a,0x717b2cf60cc5416eb3f1666e79f30d538f5c9038,0x5),
(0x72337b25f3486e8518d8f3a4da21724cf3977246,0xff88c0ddcdcdfb98ca50b68c035434ee2e81cd1d,0x748e1c374d1efdcb3b9bd7b3c812213ddc1ab940,0x4),
(0xa71275186b7bbc9747c5831b1e4c75f1bd3eae7a,0x43b995ded8fddfa6365a51d547456376c8f79b88,0x6c9a0e390dc7d40900f412313dfe0deb8a5cbb45,0x6),
(0x926bff0ea87d5c1e8c9da39ceb01a10d1b3c0709,0xaeb5012cbaf479dd3c2d297ba3a80d344ab22f57,0xa3eff29dffaed0371d860e291c8f65eb287918ce,0x3),
(0xdc9e51d365f8a827988cf70c4913d987343dc74a,0xa6940f2d3f38d0d4b20c36b24f4f91b5bdee59c1,0xb3a7373eeaf10e449aca7e3cc00f6f554ff0473f,0x4),
(0x2bcbef8732ab1e591dff595cb1c979f90ebadf0c,0x3b629a50ab44f67f762dff710653c1fa995863c1,0x7425a16af106e5eba3a0f751baba95708ead3c0,0x1),
(0x6a0eadeed0b9e7e900df27d5e253968c30f0f6bd,0x47e22a97f4dfee66b8b04983bbfbfe0374fa917d,0xfadb3f2a5b347b9fa8cfdaeddecb1215f19ec707,0x7),
(0x884675226091712e22a0fbf1fa3c0de95fa09dae,0x6549eabd7fd5bc6832e2ab061fb02d0f1df6b19a,0xb660a3baf9d96985c3b8d420259003b8fc0a4410,0x2),
(0x2a81e382054ed9523f5e4d2a966252b51046325d,0x81f663abbd508d6df460a1d5a857829834a969ac,0xe51bcf400dd3fddb5b9f13fd0403b3af011f9fc6,0x4),
(0x25f6147e13fc52aaf92b1622134c52dff9ec282d,0x76e457adf428f8a1a82711584e336c0b3b70e94e,0x6af1ced8354c4bdf84fc55fef847848d4dad83e6,0x3),
(0xfe0eba650a95051d8fa04f43824d465fdad34493,0xadd5339288e5527a394a602a2f4e891dbdf8d7aa,0x169a5d1b893fa66e35ec2620bc96f73d067c9460,0x3),
(0xb8914a5d41cdd7ff1f0eed7e6eab2e79fabfde5b,0xf6673ed83fe9731508921bfc12773a19980e5345,0x83710a069298113cfc91d716a38e1584b2606033,0x5),
(0xae25b8812cc4f7fec5a14f4174328be0a254cc26,0x16381c71aa45674488d8b1a10ff0a16d4fd6c997,0xa947337c2f9d0efe9e69f3a5332c7d0887937643,0x0),
(0xd8bc55b669d86fe42448a83063aea36251b5fe75,0x8050afa80843f0162c7fa5323cf19f4f194f90ec,0x9207917cde2804eb97708cb3392610f716e8c5c,0x4),
(0xabf778fe7279f34fe6f883d56b938ec46bafb21,0xf1e96791da0ebc0981eb60fae9509f3c973d5df7,0xf3f07a604cde6a2164601357cfde0c4b2200fb44,0x5),
(0x8bbc50d04d2841668fc639c0a0f5ae2cd9f13e03,0xfa4107e471bd396a25b3853ec09a56c49343cfa3,0xaf2d6a8142fcf028ce8aabc31377c6d7c63bc9c3,0x7),
(0xd3db7034072a88a03f7a632fdc3f5a07846c79c3,0x463871a92ceba68a12ab4d02759ff1aec24c9355,0xc61b3931ecf8330d4b26b9175efa8690161d25b4,0x4),
(0x5d5672957260b5794e305ee24bccc07f8dd34d94,0x7c27bdada7014240c904d42c5a1a1e5f38ea9826,0x779a7fcc0582e3d901494a98b8d9aa1b8d5f5840,0x7),
(0x1d197eefd0a6c59ea8f3cfc69c066ce92d7f6e96,0x665a2ba8a286880c09e2c9ea9adb7479d5bc123d,0x6377c18c0cf75070627ef9613af864be815eeed6,0x4),
(0x9c7975f4b345048f7e2d3614d5fdcf162be0d920,0xf2142d01b4b7c2a5585c8458366c716729ee3329,0x1dd8903dafda53bfe000f606bceee5b31816f683,0x7),
(0x5062cb7d6e3b50df1820f5996962b5b8b1fc4617,0xaa47856eecf23e8ef0f212ed3a978f4d5564d650,0xa02ffbb157a74b3f105895cbe487c6e1da411070,0x0),
(0xcdfcb6ff93ca01a2755c0c8f0ad8ee04118e1b9e,0x1fdc78b5968fbd65351406a0e7cb6f45d9f26a01,0xcec3c44ec773a31fd3785a998e3526624a504705,0x3),
(0x65fc356da2a36d35d88c5c5792661d8fe152821c,0x20a49731ddf37504876ed4303cf8ee52426abbbe,0xf974613f265ced476f0ad2548eecffcf4b648a9e,0x7),
(0x59544b829fa1f696558ea62792b85e114e397433,0x23645dd35469fd873a73db34f1018f08ae7f2c24,0xe5a23255d9760df1f8d6c8ce1652e0480beb0b7d,0x2),
(0x8ef11fdbed1a2f64faca70aea2cac44dadd8c14c,0x640d24c485e9e04b9af2355c07cf7ad430c7ca58,0x20f0e050124bd754c13b8c2e86dbebaee2132bec,0x1),
(0x1b5ac91240f6450de7fc5208f0762501790e28b7,0x7991d2db2512b6463c201f0523ed863ce2a670e8,0xebf64515f997f18b726cd11a24276ef26505a409,0x6),
(0xba35a8c66a894fae013ac56c9d6ba538d8cbcf0b,0xcea24619e5bdd3418da925e3aebd5a3c6f64ef03,0xb9216f67fe0aa26e374b92ecf4b0c8545522785e,0x0),
(0xe4e86fdd765bc4d98bc807e3f56ad2f2ef8dbd15,0x67a9d34b95c25764e1026fd64a0cdadc4f894ef,0x57f0a006eb1ddbae5b7aaaa3e5a2740c1401c9e2,0x6),
(0xe582d66c85dda020da90ce0248057e9dff2a0120,0x8f261523dad715ddc7c992972d8cdab39a0e8920,0x2bcd65226ab00e4e1117a90b735ea287a921641a,0x2),
(0x62ac7d9437e54969456ae056289adeaefaccd6bb,0xe7a23830bdccf8e24a6aa1d84d94cff498f3958a,0x13d192adc3f46a9a2b624a3a93e6faf243e2120f,0x7),
(0xd24bfd231c4e6b4b3fe46ec642392e59bf1b7358,0x51b756a681426525f7194a66375a35185d529813,0x57a86c9d1fe7fe8ad9b05ea21239cd42bce93ca6,0x2),
(0xeb0501d2e40edeb6ecad416cfb5d12459de1f32a,0xc5a4cacf614bc7519130e6727126823d77b51c85,0xd86708d496f4e4265526247c79931bbc0351237c,0x0),
(0xb41393d8fe5adbe01ec1ae88aacf8030f990c260,0xb6997c03f903bc1add14cb98e8741647a60c62ad,0x2fa481db8208ccfa161e791631d91cc012bff387,0x5),
(0x851a5f6a1ff9ad28e22858aded0abe1d927f8f47,0xa35a9a8b26bcbf0a639efd5583c9830aa2834a61,0x71ed5887fc9b53af96793aa25285227e679923d0,0x6),
(0x36d5d74fdbb34184f56989136c19526a1e66f284,0xe2636b99dd8277a5bdf411a2ab44688704682b8b,0x8fa686e14e0c8c40f507b8e4cc8abf2d8391e13e,0x3),
(0x136e1685ce0dd8fa72c17db7f71ad3ec08201b0f,0xf8715b24f37af56cd40108e12d4cd65dfe47b18a,0x447eb0b48cd17036c130d2c9814df4452645562e,0x3),
(0x442cd9850919eef698ad67aad25dac1e609042cc,0x8879c395e3021c4c8e1d4cf3ed7556ddcfe88c98,0xaf3310936f1bf6f93698081b581b362aa4432c2f,0x0),
(0xe788598a42acba0d0b7b1f6ec9b230b44a477aad,0xad119581e7a04cf0b3b1f5197bc27d9684813b36,0x774ad198691047f7a63714bc633ebf66aa7d2e9d,0x0),
(0x96db72fa75d1f4ef567ae6b0a6a9b67b6eb925,0xb2a2d5c2c26fdf25b4ccc5981beff2fbce544bf1,0x259ef89bfdf867a25f2a45ba31e3b8f01d15ac98,0x6),
(0xfe84f3657569c6b2f6a820fe72ae29980bb3d3b6,0x81f40f3434d8a526ae3bdd9229e3b91436c195f2,0xd9ad8ce4bae25a93282b2d585a3ccc9f76c3cfd2,0x0),
(0xbd38a3ba51b95b74301f1a375039aadf45cf9500,0x981371c31ca751800cd9554d120390faa176f90,0xc687f4008be79d2f747d0d3d373d2908dc99f863,0x0),
(0x5cf2a3d05d937cb49929f7a5420c77a510f9b9db,0x43b40c9c33d53a2c03193c499ef7f99c19d36ed2,0x6efe5e9f33a99b6d6e2b072c52923bbbc6050ee0,0x4),
(0xb3096421f5e4056f23b5bab000b764a049bff24d,0x8f826e2bce70b6aa6ec454bc8e9e8cd851ebb165,0xbb9e3082a3a1bd77fd66bb03772219a944f03e29,0x7),
(0x3dd4cead2e79dcf86cc7917a579a2dba900bb099,0x7f75439b0103ed40729a24e7f9846b7c2ca3558,0x2ebb76dc34c83a60571f14cdf6f8261988a902bd,0x7),
(0x3180aeb53046ca485f501895ed61e57e8ed27b7,0x7efbf45c158b115885fb00e2ac5b5df85eef468a,0x7c97ef4e278686bce1a424a92471b21fcf3658b6,0x3),
(0x559fa993834a40f6fd31f8a3a2f83da980b2ef84,0x8785d04f6d97d688f90af33140889e4c7201382a,0x779f8d284898ca25426208f3a6c3b9455c70eb0d,0x7),
(0x49a0f529e86a638d1cb71dbd948357d390646128,0xc5c72505c3807890a11502cfc0286fdf40c924bd,0xdc242283b58e5d98803c067a4633590e5d1e5d9e,0x1),
(0xef75ace89af3a7791034ae6161e608384984eb34,0x61a4d32ca6bdf4f8559cf15bc9be41721575650,0x8fd9e8a6cdd86a2d960409b124453245b1c92f09,0x5),
(0xcf0cf859a451378f576de4e10b918fa70b0d0e02,0x66a7f51a86fe0cd0db57d2025464c1d95384c6c0,0xcc4673380c3a3cc4545e5644ebaad0ee2205af36,0x5),
(0xa973fdecf97847abfadc76a530cfaa51a544992f,0x64ebd081e1e5be70904723e1a786d9581ad4e5a5,0x58c16e616268863fce12b920e281ad4b1d9d2881,0x1),
(0x9bbcfa5f87bea52e4df986ecdb89dadf9fe7242b,0x520b4e89d3e3cd032e5c8c9cfab3f706fe49ca8c,0x198aa5c2cab8d22845c4f3ea8f710becaba98d13,0x3),
(0x42abe9b2d14ec440b51362694f93116cf4a8980d,0x38c3965c6f9c9699476239ea669acc598bf748b6,0xb47208202e92dbc5ed3d4319dd9e4ceeb21e9ec8,0x5),
(0x334732df257a5c08e42c56dcd31f3be5cfaa196e,0xe6387cab10b4e3bff5c72b7a8c47bf3f73812e0c,0x315e28210455bc5535e6f2a6dcf5a76732ad8c88,0x3),
(0x825347e82b6ecb7c40353d9282daf9804088f22b,0xced5ac7b578c4a95a177a283f60437a70232ff0,0xb647c743e3b4ce3ca95c586bdd14afc41d91ad09,0x4),
(0xf862df8e80ded401998ce913668155e078f5863f,0xa73fe4db4136c28cbfc6ee73c800548a0bd463e2,0xff0395bc6b17d90c38ba263488be5987e3b44890,0x7)
]
n=len(data)
A=[]
C=[]
for h,r,s,b in data:
s_inv=inverse_mod(s,q)
A.append((r*s_inv)%q)
C.append(((h-b*s)*s_inv)%q)
M=Matrix(ZZ,n+1,n+1)
for i in range(n):
M[i,i]=q
for i in range(n):
M[n,i]=A[i]
M[n,n]=B
target=vector(C+[0])
M=M.stack(target)
print("[*] running LLL")
L=M.LLL()
for row in L:
d=int(row[-1])%q
if d==0:
continue
from ecdsa import SigningKey,SECP160r1
try:
sk=SigningKey.from_secret_exponent(d,curve=SECP160r1)
vk=sk.verifying_key
if vk.pubkey.point.x()==pubx and vk.pubkey.point.y()==puby:
print("d =",d)
flag="DesCTF{"+md5(str(d).encode()).hexdigest()+"}"
print("FLAG =",flag)
break
except:
pass
WP:
#先回顾一下ECDSA的基础知识,sk是私钥对象G,vk是公钥对象Q,d是私钥(G*d=Q),h是
#hash处理后的信息,随机数k,x%q=r,invert(k,q)*(h+r*d)%q=s是签名对
#这里看到泄露多组数据(达到信息论要求),并且泄露可以用a*x+b表示,识别HNP
from sage.all import *
from hashlib import md5
q = 0x100000000000000000001f4c8f927aed3ca752257
pubx = 0x8e0a0071e8cf437efec4233ff8444a4ff8adba2f
puby = 0xa869fce702b70799c443b450a4d41cc4f65b3eee
leak = 3
B = 2^leak
data = [
(0x525931a9ff8ef95025939a57275ecedc2730421f,0x5288ed7146c188ebda9b6c8909726c3d6f957891,0x334c301c2d861fa8cceecabc542a5cb7dd7df7d9,0x6),
(0x4b21047e1112dbfee487b4f23471f2fb438e268,0x82878368ef18996109bf10adae81e1acaeb9fa25,0xd4d9ec1faa9534a3fa4ff0fe78488ebf175cdfec,0x4),
(0xdd2e98102508e178fdf1e289ac8342250da6408f,0x38069b3213a57a077a38938d082a7590d0a21b95,0xcff1f76af8f15422bb288c8af372332cc6ace970,0x1),
(0xecb8547ea2a68788665e01a7025093c47f2b45de,0x6f7155ce9da5434227e48554a0bef7d7492cadb,0x53f6e1a52554436620b392dea75738b5f670d2b2,0x2),
(0xefb887600edf8d279f3cca868ef641e9284ae769,0x9caea57dd4681d1ab53029cf631a47277386bc72,0xce7743df557c732daff4595d8430ea8485ab3aca,0x3),
(0x957ec8b7a53dea95d53a5c94d595b834c2be61ca,0x1b24031194de7dac370a2f7c9be316dc14cbe3f2,0xc40b5c4c674d1f4cb99891bf342f8acebca9258b,0x5),
(0x8ba1946c16b7c8d98c6e01836ae0d791ecae07d9,0x6daec7923c03c56a18d764d9497c39871912fb1a,0x717b2cf60cc5416eb3f1666e79f30d538f5c9038,0x5),
(0x72337b25f3486e8518d8f3a4da21724cf3977246,0xff88c0ddcdcdfb98ca50b68c035434ee2e81cd1d,0x748e1c374d1efdcb3b9bd7b3c812213ddc1ab940,0x4),
(0xa71275186b7bbc9747c5831b1e4c75f1bd3eae7a,0x43b995ded8fddfa6365a51d547456376c8f79b88,0x6c9a0e390dc7d40900f412313dfe0deb8a5cbb45,0x6),
(0x926bff0ea87d5c1e8c9da39ceb01a10d1b3c0709,0xaeb5012cbaf479dd3c2d297ba3a80d344ab22f57,0xa3eff29dffaed0371d860e291c8f65eb287918ce,0x3),
(0xdc9e51d365f8a827988cf70c4913d987343dc74a,0xa6940f2d3f38d0d4b20c36b24f4f91b5bdee59c1,0xb3a7373eeaf10e449aca7e3cc00f6f554ff0473f,0x4),
(0x2bcbef8732ab1e591dff595cb1c979f90ebadf0c,0x3b629a50ab44f67f762dff710653c1fa995863c1,0x7425a16af106e5eba3a0f751baba95708ead3c0,0x1),
(0x6a0eadeed0b9e7e900df27d5e253968c30f0f6bd,0x47e22a97f4dfee66b8b04983bbfbfe0374fa917d,0xfadb3f2a5b347b9fa8cfdaeddecb1215f19ec707,0x7),
(0x884675226091712e22a0fbf1fa3c0de95fa09dae,0x6549eabd7fd5bc6832e2ab061fb02d0f1df6b19a,0xb660a3baf9d96985c3b8d420259003b8fc0a4410,0x2),
(0x2a81e382054ed9523f5e4d2a966252b51046325d,0x81f663abbd508d6df460a1d5a857829834a969ac,0xe51bcf400dd3fddb5b9f13fd0403b3af011f9fc6,0x4),
(0x25f6147e13fc52aaf92b1622134c52dff9ec282d,0x76e457adf428f8a1a82711584e336c0b3b70e94e,0x6af1ced8354c4bdf84fc55fef847848d4dad83e6,0x3),
(0xfe0eba650a95051d8fa04f43824d465fdad34493,0xadd5339288e5527a394a602a2f4e891dbdf8d7aa,0x169a5d1b893fa66e35ec2620bc96f73d067c9460,0x3),
(0xb8914a5d41cdd7ff1f0eed7e6eab2e79fabfde5b,0xf6673ed83fe9731508921bfc12773a19980e5345,0x83710a069298113cfc91d716a38e1584b2606033,0x5),
(0xae25b8812cc4f7fec5a14f4174328be0a254cc26,0x16381c71aa45674488d8b1a10ff0a16d4fd6c997,0xa947337c2f9d0efe9e69f3a5332c7d0887937643,0x0),
(0xd8bc55b669d86fe42448a83063aea36251b5fe75,0x8050afa80843f0162c7fa5323cf19f4f194f90ec,0x9207917cde2804eb97708cb3392610f716e8c5c,0x4),
(0xabf778fe7279f34fe6f883d56b938ec46bafb21,0xf1e96791da0ebc0981eb60fae9509f3c973d5df7,0xf3f07a604cde6a2164601357cfde0c4b2200fb44,0x5),
(0x8bbc50d04d2841668fc639c0a0f5ae2cd9f13e03,0xfa4107e471bd396a25b3853ec09a56c49343cfa3,0xaf2d6a8142fcf028ce8aabc31377c6d7c63bc9c3,0x7),
(0xd3db7034072a88a03f7a632fdc3f5a07846c79c3,0x463871a92ceba68a12ab4d02759ff1aec24c9355,0xc61b3931ecf8330d4b26b9175efa8690161d25b4,0x4),
(0x5d5672957260b5794e305ee24bccc07f8dd34d94,0x7c27bdada7014240c904d42c5a1a1e5f38ea9826,0x779a7fcc0582e3d901494a98b8d9aa1b8d5f5840,0x7),
(0x1d197eefd0a6c59ea8f3cfc69c066ce92d7f6e96,0x665a2ba8a286880c09e2c9ea9adb7479d5bc123d,0x6377c18c0cf75070627ef9613af864be815eeed6,0x4),
(0x9c7975f4b345048f7e2d3614d5fdcf162be0d920,0xf2142d01b4b7c2a5585c8458366c716729ee3329,0x1dd8903dafda53bfe000f606bceee5b31816f683,0x7),
(0x5062cb7d6e3b50df1820f5996962b5b8b1fc4617,0xaa47856eecf23e8ef0f212ed3a978f4d5564d650,0xa02ffbb157a74b3f105895cbe487c6e1da411070,0x0),
(0xcdfcb6ff93ca01a2755c0c8f0ad8ee04118e1b9e,0x1fdc78b5968fbd65351406a0e7cb6f45d9f26a01,0xcec3c44ec773a31fd3785a998e3526624a504705,0x3),
(0x65fc356da2a36d35d88c5c5792661d8fe152821c,0x20a49731ddf37504876ed4303cf8ee52426abbbe,0xf974613f265ced476f0ad2548eecffcf4b648a9e,0x7),
(0x59544b829fa1f696558ea62792b85e114e397433,0x23645dd35469fd873a73db34f1018f08ae7f2c24,0xe5a23255d9760df1f8d6c8ce1652e0480beb0b7d,0x2),
(0x8ef11fdbed1a2f64faca70aea2cac44dadd8c14c,0x640d24c485e9e04b9af2355c07cf7ad430c7ca58,0x20f0e050124bd754c13b8c2e86dbebaee2132bec,0x1),
(0x1b5ac91240f6450de7fc5208f0762501790e28b7,0x7991d2db2512b6463c201f0523ed863ce2a670e8,0xebf64515f997f18b726cd11a24276ef26505a409,0x6),
(0xba35a8c66a894fae013ac56c9d6ba538d8cbcf0b,0xcea24619e5bdd3418da925e3aebd5a3c6f64ef03,0xb9216f67fe0aa26e374b92ecf4b0c8545522785e,0x0),
(0xe4e86fdd765bc4d98bc807e3f56ad2f2ef8dbd15,0x67a9d34b95c25764e1026fd64a0cdadc4f894ef,0x57f0a006eb1ddbae5b7aaaa3e5a2740c1401c9e2,0x6),
(0xe582d66c85dda020da90ce0248057e9dff2a0120,0x8f261523dad715ddc7c992972d8cdab39a0e8920,0x2bcd65226ab00e4e1117a90b735ea287a921641a,0x2),
(0x62ac7d9437e54969456ae056289adeaefaccd6bb,0xe7a23830bdccf8e24a6aa1d84d94cff498f3958a,0x13d192adc3f46a9a2b624a3a93e6faf243e2120f,0x7),
(0xd24bfd231c4e6b4b3fe46ec642392e59bf1b7358,0x51b756a681426525f7194a66375a35185d529813,0x57a86c9d1fe7fe8ad9b05ea21239cd42bce93ca6,0x2),
(0xeb0501d2e40edeb6ecad416cfb5d12459de1f32a,0xc5a4cacf614bc7519130e6727126823d77b51c85,0xd86708d496f4e4265526247c79931bbc0351237c,0x0),
(0xb41393d8fe5adbe01ec1ae88aacf8030f990c260,0xb6997c03f903bc1add14cb98e8741647a60c62ad,0x2fa481db8208ccfa161e791631d91cc012bff387,0x5),
(0x851a5f6a1ff9ad28e22858aded0abe1d927f8f47,0xa35a9a8b26bcbf0a639efd5583c9830aa2834a61,0x71ed5887fc9b53af96793aa25285227e679923d0,0x6),
(0x36d5d74fdbb34184f56989136c19526a1e66f284,0xe2636b99dd8277a5bdf411a2ab44688704682b8b,0x8fa686e14e0c8c40f507b8e4cc8abf2d8391e13e,0x3),
(0x136e1685ce0dd8fa72c17db7f71ad3ec08201b0f,0xf8715b24f37af56cd40108e12d4cd65dfe47b18a,0x447eb0b48cd17036c130d2c9814df4452645562e,0x3),
(0x442cd9850919eef698ad67aad25dac1e609042cc,0x8879c395e3021c4c8e1d4cf3ed7556ddcfe88c98,0xaf3310936f1bf6f93698081b581b362aa4432c2f,0x0),
(0xe788598a42acba0d0b7b1f6ec9b230b44a477aad,0xad119581e7a04cf0b3b1f5197bc27d9684813b36,0x774ad198691047f7a63714bc633ebf66aa7d2e9d,0x0),
(0x96db72fa75d1f4ef567ae6b0a6a9b67b6eb925,0xb2a2d5c2c26fdf25b4ccc5981beff2fbce544bf1,0x259ef89bfdf867a25f2a45ba31e3b8f01d15ac98,0x6),
(0xfe84f3657569c6b2f6a820fe72ae29980bb3d3b6,0x81f40f3434d8a526ae3bdd9229e3b91436c195f2,0xd9ad8ce4bae25a93282b2d585a3ccc9f76c3cfd2,0x0),
(0xbd38a3ba51b95b74301f1a375039aadf45cf9500,0x981371c31ca751800cd9554d120390faa176f90,0xc687f4008be79d2f747d0d3d373d2908dc99f863,0x0),
(0x5cf2a3d05d937cb49929f7a5420c77a510f9b9db,0x43b40c9c33d53a2c03193c499ef7f99c19d36ed2,0x6efe5e9f33a99b6d6e2b072c52923bbbc6050ee0,0x4),
(0xb3096421f5e4056f23b5bab000b764a049bff24d,0x8f826e2bce70b6aa6ec454bc8e9e8cd851ebb165,0xbb9e3082a3a1bd77fd66bb03772219a944f03e29,0x7),
(0x3dd4cead2e79dcf86cc7917a579a2dba900bb099,0x7f75439b0103ed40729a24e7f9846b7c2ca3558,0x2ebb76dc34c83a60571f14cdf6f8261988a902bd,0x7),
(0x3180aeb53046ca485f501895ed61e57e8ed27b7,0x7efbf45c158b115885fb00e2ac5b5df85eef468a,0x7c97ef4e278686bce1a424a92471b21fcf3658b6,0x3),
(0x559fa993834a40f6fd31f8a3a2f83da980b2ef84,0x8785d04f6d97d688f90af33140889e4c7201382a,0x779f8d284898ca25426208f3a6c3b9455c70eb0d,0x7),
(0x49a0f529e86a638d1cb71dbd948357d390646128,0xc5c72505c3807890a11502cfc0286fdf40c924bd,0xdc242283b58e5d98803c067a4633590e5d1e5d9e,0x1),
(0xef75ace89af3a7791034ae6161e608384984eb34,0x61a4d32ca6bdf4f8559cf15bc9be41721575650,0x8fd9e8a6cdd86a2d960409b124453245b1c92f09,0x5),
(0xcf0cf859a451378f576de4e10b918fa70b0d0e02,0x66a7f51a86fe0cd0db57d2025464c1d95384c6c0,0xcc4673380c3a3cc4545e5644ebaad0ee2205af36,0x5),
(0xa973fdecf97847abfadc76a530cfaa51a544992f,0x64ebd081e1e5be70904723e1a786d9581ad4e5a5,0x58c16e616268863fce12b920e281ad4b1d9d2881,0x1),
(0x9bbcfa5f87bea52e4df986ecdb89dadf9fe7242b,0x520b4e89d3e3cd032e5c8c9cfab3f706fe49ca8c,0x198aa5c2cab8d22845c4f3ea8f710becaba98d13,0x3),
(0x42abe9b2d14ec440b51362694f93116cf4a8980d,0x38c3965c6f9c9699476239ea669acc598bf748b6,0xb47208202e92dbc5ed3d4319dd9e4ceeb21e9ec8,0x5),
(0x334732df257a5c08e42c56dcd31f3be5cfaa196e,0xe6387cab10b4e3bff5c72b7a8c47bf3f73812e0c,0x315e28210455bc5535e6f2a6dcf5a76732ad8c88,0x3),
(0x825347e82b6ecb7c40353d9282daf9804088f22b,0xced5ac7b578c4a95a177a283f60437a70232ff0,0xb647c743e3b4ce3ca95c586bdd14afc41d91ad09,0x4),
(0xf862df8e80ded401998ce913668155e078f5863f,0xa73fe4db4136c28cbfc6ee73c800548a0bd463e2,0xff0395bc6b17d90c38ba263488be5987e3b44890,0x7)
]
n=len(data)
A=[]
C=[]
for h,r,s,b in data:
s_inv=inverse_mod(s,q)
A.append((r*s_inv)%q)
C.append(((h-b*s)*s_inv)%q)#HNP化简
M=Matrix(ZZ,n+1,n+1)
for i in range(n):
M[i,i]=q
for i in range(n):
M[n,i]=A[i]
M[n,n]=B
target=vector(C+[0])
M=M.stack(target)#这里表示把这行加到底下
print("[*] running LLL")
L=M.LLL()
for row in L:
d=int(row[-1])%q
if d==0:
continue
from ecdsa import SigningKey,SECP160r1
try:
sk=SigningKey.from_secret_exponent(d,curve=SECP160r1)
vk=sk.verifying_key
#这里是检查,用G&自己算出来的d的x,y是否符合题上提供的x,y
if vk.pubkey.point.x()==pubx and vk.pubkey.point.y()==puby:
print("d =",d)
flag="DesCTF{"+md5(str(d).encode()).hexdigest()+"}"
print("FLAG =",flag)
break
except:
pass
WP:
#先回顾一下ECDSA的基础知识,sk是私钥对象G,vk是公钥对象Q,d是私钥(G*d=Q),h是
#hash处理后的信息,随机数k,x%q=r,invert(k,q)*(h+r*d)%q=s是签名对
#这里看到泄露多组数据(达到信息论要求),并且泄露可以用a*x+b表示,识别HNP
from sage.all import *
from hashlib import md5
q = 0x100000000000000000001f4c8f927aed3ca752257
pubx = 0x8e0a0071e8cf437efec4233ff8444a4ff8adba2f
puby = 0xa869fce702b70799c443b450a4d41cc4f65b3eee
leak = 3
B = 2^leak
data = [
(0x525931a9ff8ef95025939a57275ecedc2730421f,0x5288ed7146c188ebda9b6c8909726c3d6f957891,0x334c301c2d861fa8cceecabc542a5cb7dd7df7d9,0x6),
(0x4b21047e1112dbfee487b4f23471f2fb438e268,0x82878368ef18996109bf10adae81e1acaeb9fa25,0xd4d9ec1faa9534a3fa4ff0fe78488ebf175cdfec,0x4),
(0xdd2e98102508e178fdf1e289ac8342250da6408f,0x38069b3213a57a077a38938d082a7590d0a21b95,0xcff1f76af8f15422bb288c8af372332cc6ace970,0x1),
(0xecb8547ea2a68788665e01a7025093c47f2b45de,0x6f7155ce9da5434227e48554a0bef7d7492cadb,0x53f6e1a52554436620b392dea75738b5f670d2b2,0x2),
(0xefb887600edf8d279f3cca868ef641e9284ae769,0x9caea57dd4681d1ab53029cf631a47277386bc72,0xce7743df557c732daff4595d8430ea8485ab3aca,0x3),
(0x957ec8b7a53dea95d53a5c94d595b834c2be61ca,0x1b24031194de7dac370a2f7c9be316dc14cbe3f2,0xc40b5c4c674d1f4cb99891bf342f8acebca9258b,0x5),
(0x8ba1946c16b7c8d98c6e01836ae0d791ecae07d9,0x6daec7923c03c56a18d764d9497c39871912fb1a,0x717b2cf60cc5416eb3f1666e79f30d538f5c9038,0x5),
(0x72337b25f3486e8518d8f3a4da21724cf3977246,0xff88c0ddcdcdfb98ca50b68c035434ee2e81cd1d,0x748e1c374d1efdcb3b9bd7b3c812213ddc1ab940,0x4),
(0xa71275186b7bbc9747c5831b1e4c75f1bd3eae7a,0x43b995ded8fddfa6365a51d547456376c8f79b88,0x6c9a0e390dc7d40900f412313dfe0deb8a5cbb45,0x6),
(0x926bff0ea87d5c1e8c9da39ceb01a10d1b3c0709,0xaeb5012cbaf479dd3c2d297ba3a80d344ab22f57,0xa3eff29dffaed0371d860e291c8f65eb287918ce,0x3),
(0xdc9e51d365f8a827988cf70c4913d987343dc74a,0xa6940f2d3f38d0d4b20c36b24f4f91b5bdee59c1,0xb3a7373eeaf10e449aca7e3cc00f6f554ff0473f,0x4),
(0x2bcbef8732ab1e591dff595cb1c979f90ebadf0c,0x3b629a50ab44f67f762dff710653c1fa995863c1,0x7425a16af106e5eba3a0f751baba95708ead3c0,0x1),
(0x6a0eadeed0b9e7e900df27d5e253968c30f0f6bd,0x47e22a97f4dfee66b8b04983bbfbfe0374fa917d,0xfadb3f2a5b347b9fa8cfdaeddecb1215f19ec707,0x7),
(0x884675226091712e22a0fbf1fa3c0de95fa09dae,0x6549eabd7fd5bc6832e2ab061fb02d0f1df6b19a,0xb660a3baf9d96985c3b8d420259003b8fc0a4410,0x2),
(0x2a81e382054ed9523f5e4d2a966252b51046325d,0x81f663abbd508d6df460a1d5a857829834a969ac,0xe51bcf400dd3fddb5b9f13fd0403b3af011f9fc6,0x4),
(0x25f6147e13fc52aaf92b1622134c52dff9ec282d,0x76e457adf428f8a1a82711584e336c0b3b70e94e,0x6af1ced8354c4bdf84fc55fef847848d4dad83e6,0x3),
(0xfe0eba650a95051d8fa04f43824d465fdad34493,0xadd5339288e5527a394a602a2f4e891dbdf8d7aa,0x169a5d1b893fa66e35ec2620bc96f73d067c9460,0x3),
(0xb8914a5d41cdd7ff1f0eed7e6eab2e79fabfde5b,0xf6673ed83fe9731508921bfc12773a19980e5345,0x83710a069298113cfc91d716a38e1584b2606033,0x5),
(0xae25b8812cc4f7fec5a14f4174328be0a254cc26,0x16381c71aa45674488d8b1a10ff0a16d4fd6c997,0xa947337c2f9d0efe9e69f3a5332c7d0887937643,0x0),
(0xd8bc55b669d86fe42448a83063aea36251b5fe75,0x8050afa80843f0162c7fa5323cf19f4f194f90ec,0x9207917cde2804eb97708cb3392610f716e8c5c,0x4),
(0xabf778fe7279f34fe6f883d56b938ec46bafb21,0xf1e96791da0ebc0981eb60fae9509f3c973d5df7,0xf3f07a604cde6a2164601357cfde0c4b2200fb44,0x5),
(0x8bbc50d04d2841668fc639c0a0f5ae2cd9f13e03,0xfa4107e471bd396a25b3853ec09a56c49343cfa3,0xaf2d6a8142fcf028ce8aabc31377c6d7c63bc9c3,0x7),
(0xd3db7034072a88a03f7a632fdc3f5a07846c79c3,0x463871a92ceba68a12ab4d02759ff1aec24c9355,0xc61b3931ecf8330d4b26b9175efa8690161d25b4,0x4),
(0x5d5672957260b5794e305ee24bccc07f8dd34d94,0x7c27bdada7014240c904d42c5a1a1e5f38ea9826,0x779a7fcc0582e3d901494a98b8d9aa1b8d5f5840,0x7),
(0x1d197eefd0a6c59ea8f3cfc69c066ce92d7f6e96,0x665a2ba8a286880c09e2c9ea9adb7479d5bc123d,0x6377c18c0cf75070627ef9613af864be815eeed6,0x4),
(0x9c7975f4b345048f7e2d3614d5fdcf162be0d920,0xf2142d01b4b7c2a5585c8458366c716729ee3329,0x1dd8903dafda53bfe000f606bceee5b31816f683,0x7),
(0x5062cb7d6e3b50df1820f5996962b5b8b1fc4617,0xaa47856eecf23e8ef0f212ed3a978f4d5564d650,0xa02ffbb157a74b3f105895cbe487c6e1da411070,0x0),
(0xcdfcb6ff93ca01a2755c0c8f0ad8ee04118e1b9e,0x1fdc78b5968fbd65351406a0e7cb6f45d9f26a01,0xcec3c44ec773a31fd3785a998e3526624a504705,0x3),
(0x65fc356da2a36d35d88c5c5792661d8fe152821c,0x20a49731ddf37504876ed4303cf8ee52426abbbe,0xf974613f265ced476f0ad2548eecffcf4b648a9e,0x7),
(0x59544b829fa1f696558ea62792b85e114e397433,0x23645dd35469fd873a73db34f1018f08ae7f2c24,0xe5a23255d9760df1f8d6c8ce1652e0480beb0b7d,0x2),
(0x8ef11fdbed1a2f64faca70aea2cac44dadd8c14c,0x640d24c485e9e04b9af2355c07cf7ad430c7ca58,0x20f0e050124bd754c13b8c2e86dbebaee2132bec,0x1),
(0x1b5ac91240f6450de7fc5208f0762501790e28b7,0x7991d2db2512b6463c201f0523ed863ce2a670e8,0xebf64515f997f18b726cd11a24276ef26505a409,0x6),
(0xba35a8c66a894fae013ac56c9d6ba538d8cbcf0b,0xcea24619e5bdd3418da925e3aebd5a3c6f64ef03,0xb9216f67fe0aa26e374b92ecf4b0c8545522785e,0x0),
(0xe4e86fdd765bc4d98bc807e3f56ad2f2ef8dbd15,0x67a9d34b95c25764e1026fd64a0cdadc4f894ef,0x57f0a006eb1ddbae5b7aaaa3e5a2740c1401c9e2,0x6),
(0xe582d66c85dda020da90ce0248057e9dff2a0120,0x8f261523dad715ddc7c992972d8cdab39a0e8920,0x2bcd65226ab00e4e1117a90b735ea287a921641a,0x2),
(0x62ac7d9437e54969456ae056289adeaefaccd6bb,0xe7a23830bdccf8e24a6aa1d84d94cff498f3958a,0x13d192adc3f46a9a2b624a3a93e6faf243e2120f,0x7),
(0xd24bfd231c4e6b4b3fe46ec642392e59bf1b7358,0x51b756a681426525f7194a66375a35185d529813,0x57a86c9d1fe7fe8ad9b05ea21239cd42bce93ca6,0x2),
(0xeb0501d2e40edeb6ecad416cfb5d12459de1f32a,0xc5a4cacf614bc7519130e6727126823d77b51c85,0xd86708d496f4e4265526247c79931bbc0351237c,0x0),
(0xb41393d8fe5adbe01ec1ae88aacf8030f990c260,0xb6997c03f903bc1add14cb98e8741647a60c62ad,0x2fa481db8208ccfa161e791631d91cc012bff387,0x5),
(0x851a5f6a1ff9ad28e22858aded0abe1d927f8f47,0xa35a9a8b26bcbf0a639efd5583c9830aa2834a61,0x71ed5887fc9b53af96793aa25285227e679923d0,0x6),
(0x36d5d74fdbb34184f56989136c19526a1e66f284,0xe2636b99dd8277a5bdf411a2ab44688704682b8b,0x8fa686e14e0c8c40f507b8e4cc8abf2d8391e13e,0x3),
(0x136e1685ce0dd8fa72c17db7f71ad3ec08201b0f,0xf8715b24f37af56cd40108e12d4cd65dfe47b18a,0x447eb0b48cd17036c130d2c9814df4452645562e,0x3),
(0x442cd9850919eef698ad67aad25dac1e609042cc,0x8879c395e3021c4c8e1d4cf3ed7556ddcfe88c98,0xaf3310936f1bf6f93698081b581b362aa4432c2f,0x0),
(0xe788598a42acba0d0b7b1f6ec9b230b44a477aad,0xad119581e7a04cf0b3b1f5197bc27d9684813b36,0x774ad198691047f7a63714bc633ebf66aa7d2e9d,0x0),
(0x96db72fa75d1f4ef567ae6b0a6a9b67b6eb925,0xb2a2d5c2c26fdf25b4ccc5981beff2fbce544bf1,0x259ef89bfdf867a25f2a45ba31e3b8f01d15ac98,0x6),
(0xfe84f3657569c6b2f6a820fe72ae29980bb3d3b6,0x81f40f3434d8a526ae3bdd9229e3b91436c195f2,0xd9ad8ce4bae25a93282b2d585a3ccc9f76c3cfd2,0x0),
(0xbd38a3ba51b95b74301f1a375039aadf45cf9500,0x981371c31ca751800cd9554d120390faa176f90,0xc687f4008be79d2f747d0d3d373d2908dc99f863,0x0),
(0x5cf2a3d05d937cb49929f7a5420c77a510f9b9db,0x43b40c9c33d53a2c03193c499ef7f99c19d36ed2,0x6efe5e9f33a99b6d6e2b072c52923bbbc6050ee0,0x4),
(0xb3096421f5e4056f23b5bab000b764a049bff24d,0x8f826e2bce70b6aa6ec454bc8e9e8cd851ebb165,0xbb9e3082a3a1bd77fd66bb03772219a944f03e29,0x7),
(0x3dd4cead2e79dcf86cc7917a579a2dba900bb099,0x7f75439b0103ed40729a24e7f9846b7c2ca3558,0x2ebb76dc34c83a60571f14cdf6f8261988a902bd,0x7),
(0x3180aeb53046ca485f501895ed61e57e8ed27b7,0x7efbf45c158b115885fb00e2ac5b5df85eef468a,0x7c97ef4e278686bce1a424a92471b21fcf3658b6,0x3),
(0x559fa993834a40f6fd31f8a3a2f83da980b2ef84,0x8785d04f6d97d688f90af33140889e4c7201382a,0x779f8d284898ca25426208f3a6c3b9455c70eb0d,0x7),
(0x49a0f529e86a638d1cb71dbd948357d390646128,0xc5c72505c3807890a11502cfc0286fdf40c924bd,0xdc242283b58e5d98803c067a4633590e5d1e5d9e,0x1),
(0xef75ace89af3a7791034ae6161e608384984eb34,0x61a4d32ca6bdf4f8559cf15bc9be41721575650,0x8fd9e8a6cdd86a2d960409b124453245b1c92f09,0x5),
(0xcf0cf859a451378f576de4e10b918fa70b0d0e02,0x66a7f51a86fe0cd0db57d2025464c1d95384c6c0,0xcc4673380c3a3cc4545e5644ebaad0ee2205af36,0x5),
(0xa973fdecf97847abfadc76a530cfaa51a544992f,0x64ebd081e1e5be70904723e1a786d9581ad4e5a5,0x58c16e616268863fce12b920e281ad4b1d9d2881,0x1),
(0x9bbcfa5f87bea52e4df986ecdb89dadf9fe7242b,0x520b4e89d3e3cd032e5c8c9cfab3f706fe49ca8c,0x198aa5c2cab8d22845c4f3ea8f710becaba98d13,0x3),
(0x42abe9b2d14ec440b51362694f93116cf4a8980d,0x38c3965c6f9c9699476239ea669acc598bf748b6,0xb47208202e92dbc5ed3d4319dd9e4ceeb21e9ec8,0x5),
(0x334732df257a5c08e42c56dcd31f3be5cfaa196e,0xe6387cab10b4e3bff5c72b7a8c47bf3f73812e0c,0x315e28210455bc5535e6f2a6dcf5a76732ad8c88,0x3),
(0x825347e82b6ecb7c40353d9282daf9804088f22b,0xced5ac7b578c4a95a177a283f60437a70232ff0,0xb647c743e3b4ce3ca95c586bdd14afc41d91ad09,0x4),
(0xf862df8e80ded401998ce913668155e078f5863f,0xa73fe4db4136c28cbfc6ee73c800548a0bd463e2,0xff0395bc6b17d90c38ba263488be5987e3b44890,0x7)
]
n=len(data)
A=[]
C=[]
for h,r,s,b in data:
s_inv=inverse_mod(s,q)
A.append((r*s_inv)%q)
C.append(((h-b*s)*s_inv)%q)#HNP化简
M=Matrix(ZZ,n+1,n+1)
for i in range(n):
M[i,i]=q
for i in range(n):
M[n,i]=A[i]
M[n,n]=B
target=vector(C+[0])
M=M.stack(target)#这里表示把这行加到底下
print("[*] running LLL")
L=M.LLL()
for row in L:
d=int(row[-1])%q
if d==0:
continue
from ecdsa import SigningKey,SECP160r1
try:
sk=SigningKey.from_secret_exponent(d,curve=SECP160r1)
vk=sk.verifying_key
#这里是检查,用G&自己算出来的d的x,y是否符合题上提供的x,y
if vk.pubkey.point.x()==pubx and vk.pubkey.point.y()==puby:
print("d =",d)
flag="DesCTF{"+md5(str(d).encode()).hexdigest()+"}"
print("FLAG =",flag)
break
except:
pass
HNP泄露
至此,4道题AK,结束,继续学习

发表回复